Two Page Login with Spring Security 3.2.x. ![]() Cannot retrieve string(s) from preferences (settings).Read input from a JOptionPane.showInputDialog box.I need to know how to get my program to output the word i typed in and also the new rearranged word using a 2D array.Are all Spring Framework Java Configuration injection examples buggy?.String method cannot be found in a main class method.java doesn't run if structure inside of onclick listener.When to create variables (memory management).getting " (1) no such column: _id10 " error.My eclipse won't open, i download the bundle pack it keeps saying error log.How to split a string in two and store it in a field.How do I get some variable from another class in Java?.How to implement a simple scenario the OO way.How much should a function trust another function.Under what circumstances can I call findViewById with an Options Menu / Action Bar item?.Although, I had to accept a warning which added a security exception for the website since the certificate used is a self-signed one. This time when I tried accessing the application from the browser using: In my case it was: https:35.123.45.6:8443 So the full server configuration for the application looked liked this in the Tomcat server configuration file ( /opt/tomcat/conf/server.xml): ![]() Also a port for the https protocol is defined, which is different from the port for the http protocol: Notice that the keystore file location and password are specified. Next, I added a https Tomcat server connector for the application in the Tomcat server configuration file ( /opt/tomcat/conf/server.xml): sudo nano /opt/tomcat/conf/server.xmlĪdd the following to the configuration of the application. Java can be installed using sudo apt install default-jdk. Note: You need to have Java installed on the server to be able to do this. I first had to create a keystore file for the application, more like a self-signed certificate for the https protocol: sudo keytool -genkey -keyalg RSA -alias tomcat -keystore /usr/share/tomcat.keystore You need a certificate to setup the https protocol for the application. I however tried using the https protocol in the browser but it didn't connect throwing the error: So when I try running the application I get this error in my log file: 11.AbstractHttp11Processor process The issue was that the application already had https defined as it's default protocol while I was using http to call the application in the browser. I had this issue when working on a Java Project in Debian 10 with Tomcat as the application server. What has changed in Tomcat 7.0.43? What do I have to change? ![]() Here is the access log for that request: "GET /socket/notification/848df2e62fcf93e1b3?X-Atmosphere-tracking-id=0&X-Atmosphere-Framework=2.0.2-javascript&X-Atmosphere-Transport=websocket&X-Atmosphere-TrackMessageSize=true&X-Cache-Date=0&Content-Type=application/json %20charset=UTF-8&X-atmo-protocol=true HTTP/1.1" My browser console shows the following: WebSocket connection to 'ws://failed: Unrecognized frame opcode: 5 Note: further occurrences of HTTP header parsing errors will be logged at DEBUG level. My app works fine in Tomcat 7.0.42 but with 43 I get the following output when I try to access my server on websockets: 3:08:34 AM 11.AbstractHttp11Processor process I use Tomcat 7.0.43 with a websocket application.
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